Today's Linkster #50 · NFL

Darius Slay to Jacoby Brissett

On Tuesday, October 20, 2026, everyone playing the NFL Today's Linkster got the same two players: get from Darius Slay to Jacoby Brissett in as few links as possible. Par was 3, counted through colleges, but any shared college, jersey number or team counted as a move.

The two players

  • Darius Slay (CB, 2017–2025) College: Itawamba JC and Mississippi State. Teams: Detroit Lions, Philadelphia Eagles and Pittsburgh Steelers. Numbers: #2, #23 and #24.
  • Jacoby Brissett (QB, 2017–2026) College: Florida and N.C. State. Teams: Arizona Cardinals, Cleveland Browns, Indianapolis Colts, Miami Dolphins, New England Patriots and Washington Commanders. Numbers: #7, #12 and #14.

Seasons 2017–2026. Jersey numbers and teams only count from seasons in that range.

How it went

42 players solved it on the day (2 more gave up). 30 beat par with a shortcut, and 39 matched or beat it in all. The winning run was dsamson9's: 2 moves in 0:11.3.

The answer

Show a shortest route

Through colleges alone it takes 3, which is par:

  1. Darius Slay
  2. Mississippi State Malik Heath
  3. Mississippi Van Jefferson
  4. Florida Jacoby Brissett

With every kind of link counting, it could be done in 2:

  1. Darius Slay
  2. Pittsburgh Steelers Jalen Ramsey
  3. Miami Dolphins Jacoby Brissett