Today's Linkster #50 · NFL
Darius Slay to Jacoby Brissett
On Tuesday, October 20, 2026, everyone playing the NFL Today's Linkster got the same two players: get from Darius Slay to Jacoby Brissett in as few links as possible. Par was 3, counted through colleges, but any shared college, jersey number or team counted as a move.
The two players
- Darius Slay College: Itawamba JC and Mississippi State. Teams: Detroit Lions, Philadelphia Eagles and Pittsburgh Steelers. Numbers: #2, #23 and #24.
- Jacoby Brissett College: Florida and N.C. State. Teams: Arizona Cardinals, Cleveland Browns, Indianapolis Colts, Miami Dolphins, New England Patriots and Washington Commanders. Numbers: #7, #12 and #14.
How it went
42 players solved it on the day (2 more gave up). 30 beat par with a shortcut, and 39 matched or beat it in all. The winning run was dsamson9's: 2 moves in 0:11.3.
The answer
Show a shortest route
Through colleges alone it takes 3, which is par:
- Darius Slay
- Mississippi State Malik Heath
- Mississippi Van Jefferson
- Florida Jacoby Brissett
With every kind of link counting, it could be done in 2:
- Darius Slay
- Pittsburgh Steelers Jalen Ramsey
- Miami Dolphins Jacoby Brissett